![]() ∴ Area of quadrilateral PQOR = 2 x ar ∆OQPĪt one end A of a diameter AB of a circle of radius 5 cm, tangent XAY is drawn to the circle. Now, area of ∆OQP = \(\frac \) x 12 x 5 = 30 cm 2 P is a point at a distance of 13 cm from O. (A) Firstly, draw a circle of radius 5 cm with centre O. Then the area of the quadrilateral PQOR is Therefore, OA is perpendicular to AT.įrom a point P which is at a distance of 13 cm from the centre O of a circle of radius 5 cm, the pair of tangents PQ and PR to the circle are drawn. Since, AT is the tangent to the circle at point A. We know that, diameter subtends an angle 90° at the circle. (C) In figure, AOC is a diameter of the circle. ![]() If AT is the tangent to the circle at the point A, then ∠BAT is equal to In figure, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. (D) We know that the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle. In figure, if ∠AOB = 125°, then ∠COD is equal to ∴ Length of chord AC = 2BC = 2 x 3 = 6 cm Now, we draw a chord AC of circle C 2, which touches the circle Q at B.Īlso, join OB, which is perpendicular to AC. (B) Let O be the centre of two concentric circles C 1 and C 2, whose radii are r 1 = 4 cm and r 2 = 5 cm. If radii of two concentric circles are 4 cm and 5 cm, then the length of each chord of one circle which is tangent to the other circle is NCERT Exemplar Class 10 Maths Chapter 9 CirclesĬhoose the correct answer from the given four options: Here we have given NCERT Exemplar Class 10 Maths Chapter 9 Circles. NCERT Exemplar Class 10 Maths Chapter 9 Circles are part of NCERT Exemplar Class 10 Maths. Lakhmir Singh Science Class 8 Solutions.PS Verma and VK Agarwal Biology Class 9 Solutions.NCERT Solutions for Class 9 Foundation of IT.NCERT Solutions for Class 9 Social Science.NCERT Solutions for Class 10 Foundation of Information Technology.NCERT Solutions For Class 10 Hindi Kritika.NCERT Solutions For Class 10 Hindi Kshitiz. ![]()
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